Integrand size = 24, antiderivative size = 48 \[ \int \frac {(e x)^m}{(a+b x) (a c-b c x)} \, dx=\frac {(e x)^{1+m} \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{2},\frac {3+m}{2},\frac {b^2 x^2}{a^2}\right )}{a^2 c e (1+m)} \]
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Time = 0.01 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {74, 371} \[ \int \frac {(e x)^m}{(a+b x) (a c-b c x)} \, dx=\frac {(e x)^{m+1} \operatorname {Hypergeometric2F1}\left (1,\frac {m+1}{2},\frac {m+3}{2},\frac {b^2 x^2}{a^2}\right )}{a^2 c e (m+1)} \]
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Rule 74
Rule 371
Rubi steps \begin{align*} \text {integral}& = \int \frac {(e x)^m}{a^2 c-b^2 c x^2} \, dx \\ & = \frac {(e x)^{1+m} \, _2F_1\left (1,\frac {1+m}{2};\frac {3+m}{2};\frac {b^2 x^2}{a^2}\right )}{a^2 c e (1+m)} \\ \end{align*}
Time = 0.12 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.96 \[ \int \frac {(e x)^m}{(a+b x) (a c-b c x)} \, dx=\frac {x (e x)^m \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{2},1+\frac {1+m}{2},\frac {b^2 x^2}{a^2}\right )}{a^2 c (1+m)} \]
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\[\int \frac {\left (e x \right )^{m}}{\left (b x +a \right ) \left (-b c x +a c \right )}d x\]
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\[ \int \frac {(e x)^m}{(a+b x) (a c-b c x)} \, dx=\int { -\frac {\left (e x\right )^{m}}{{\left (b c x - a c\right )} {\left (b x + a\right )}} \,d x } \]
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Result contains complex when optimal does not.
Time = 0.90 (sec) , antiderivative size = 88, normalized size of antiderivative = 1.83 \[ \int \frac {(e x)^m}{(a+b x) (a c-b c x)} \, dx=\frac {a^{- m} a^{m - 1} b^{m} b^{- m - 1} e^{m} m x^{m} \Phi \left (\frac {b x e^{i \pi }}{a}, 1, m\right ) \Gamma \left (- m\right )}{2 c \Gamma \left (1 - m\right )} - \frac {e^{m} m x^{m} \Phi \left (\frac {a}{b x}, 1, m e^{i \pi }\right ) \Gamma \left (- m\right )}{2 a b c \Gamma \left (1 - m\right )} \]
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\[ \int \frac {(e x)^m}{(a+b x) (a c-b c x)} \, dx=\int { -\frac {\left (e x\right )^{m}}{{\left (b c x - a c\right )} {\left (b x + a\right )}} \,d x } \]
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\[ \int \frac {(e x)^m}{(a+b x) (a c-b c x)} \, dx=\int { -\frac {\left (e x\right )^{m}}{{\left (b c x - a c\right )} {\left (b x + a\right )}} \,d x } \]
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Timed out. \[ \int \frac {(e x)^m}{(a+b x) (a c-b c x)} \, dx=\int \frac {{\left (e\,x\right )}^m}{\left (a\,c-b\,c\,x\right )\,\left (a+b\,x\right )} \,d x \]
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